#include <mutex>
#include <thread>
#include <iostream>
#include <vector>
#include <functional>
#include <chrono>
#include <string>
 
struct Employee {
    Employee(std::string id) : id(id) {}
    std::string id;
    std::vector<std::string> lunch_partners;
    std::mutex m;
    std::string output() const
    {
        std::string ret = "Employee " + id + " has lunch partners: ";
        for( const auto& partner : lunch_partners )
            ret += partner + " ";
        return ret;
    }
};
 
void send_mail(Employee &, Employee &)
{
    // 模拟耗时的发信操作
    std::this_thread::sleep_for(std::chrono::seconds(1));
}
 
void assign_lunch_partner(Employee &e1, Employee &e2)
{
    static std::mutex io_mutex;
    {
        std::lock_guard<std::mutex> lk(io_mutex);
        std::cout << e1.id << " and " << e2.id << " are waiting for locks" << std::endl;
    }
 
    // 用 std::lock 获得二个锁，而不担心对 assign_lunch_partner 的其他调用会死锁我们
    {
        std::lock(e1.m, e2.m);
        std::lock_guard<std::mutex> lk1(e1.m, std::adopt_lock);
        std::lock_guard<std::mutex> lk2(e2.m, std::adopt_lock);
// 等价代码（若需要 unique_locks ，例如对于条件变量）
//        std::unique_lock<std::mutex> lk1(e1.m, std::defer_lock);
//        std::unique_lock<std::mutex> lk2(e2.m, std::defer_lock);
//        std::lock(lk1, lk2);
// C++17 中可用的较优解法
//        std::scoped_lock lk(e1.m, e2.m);
        {
            std::lock_guard<std::mutex> lk(io_mutex);
            std::cout << e1.id << " and " << e2.id << " got locks" << std::endl;
        }
        e1.lunch_partners.push_back(e2.id);
        e2.lunch_partners.push_back(e1.id);
    }
    send_mail(e1, e2);
    send_mail(e2, e1);
}
 
int main()
{
    Employee alice("alice"), bob("bob"), christina("christina"), dave("dave");
 
    // 在平行线程指派，因为发邮件给用户告知午餐指派，会消耗长时间
    std::vector<std::thread> threads;
    threads.emplace_back(assign_lunch_partner, std::ref(alice), std::ref(bob));
    threads.emplace_back(assign_lunch_partner, std::ref(christina), std::ref(bob));
    threads.emplace_back(assign_lunch_partner, std::ref(christina), std::ref(alice));
    threads.emplace_back(assign_lunch_partner, std::ref(dave), std::ref(bob));
 
    for (auto &thread : threads) thread.join();
    std::cout << alice.output() << '\n'  << bob.output() << '\n'
              << christina.output() << '\n' << dave.output() << '\n';
}