operator+,-,*,/ (std::complex)
来自cppreference.com
| (1) | ||
| template< class T > std::complex<T> operator+( const std::complex<T>& lhs, const std::complex<T>& rhs); |
(C++20 前) | |
| template< class T > constexpr std::complex<T> operator+( const std::complex<T>& lhs, const std::complex<T>& rhs); |
(C++20 起) | |
| (2) | ||
| template< class T > std::complex<T> operator+( const std::complex<T>& lhs, const T& rhs); |
(C++20 前) | |
| template< class T > constexpr std::complex<T> operator+( const std::complex<T>& lhs, const T& rhs); |
(C++20 起) | |
| (3) | ||
| template< class T > std::complex<T> operator+( const T& lhs, const std::complex<T>& rhs); |
(C++20 前) | |
| template< class T > constexpr std::complex<T> operator+( const T& lhs, const std::complex<T>& rhs); |
(C++20 起) | |
| (4) | ||
| template< class T > std::complex<T> operator-( const std::complex<T>& lhs, const std::complex<T>& rhs); |
(C++20 前) | |
| template< class T > constexpr std::complex<T> operator-( const std::complex<T>& lhs, const std::complex<T>& rhs); |
(C++20 起) | |
| (5) | ||
| template< class T > std::complex<T> operator-( const std::complex<T>& lhs, const T& rhs); |
(C++20 前) | |
| template< class T > constexpr std::complex<T> operator-( const std::complex<T>& lhs, const T& rhs); |
(C++20 起) | |
| (6) | ||
| template< class T > std::complex<T> operator-( const T& lhs, const std::complex<T>& rhs); |
(C++20 前) | |
| template< class T > constexpr std::complex<T> operator-( const T& lhs, const std::complex<T>& rhs); |
(C++20 起) | |
| (7) | ||
| template< class T > std::complex<T> operator*( const std::complex<T>& lhs, const std::complex<T>& rhs); |
(C++20 前) | |
| template< class T > constexpr std::complex<T> operator*( const std::complex<T>& lhs, const std::complex<T>& rhs); |
(C++20 起) | |
| (8) | ||
| template< class T > std::complex<T> operator*( const std::complex<T>& lhs, const T& rhs); |
(C++20 前) | |
| template< class T > constexpr std::complex<T> operator*( const std::complex<T>& lhs, const T& rhs); |
(C++20 起) | |
| (9) | ||
| template< class T > std::complex<T> operator*( const T& lhs, const std::complex<T>& rhs); |
(C++20 前) | |
| template< class T > constexpr std::complex<T> operator*( const T& lhs, const std::complex<T>& rhs); |
(C++20 起) | |
| (10) | ||
| template< class T > std::complex<T> operator/( const std::complex<T>& lhs, const std::complex<T>& rhs); |
(C++20 前) | |
| template< class T > constexpr std::complex<T> operator/( const std::complex<T>& lhs, const std::complex<T>& rhs); |
(C++20 起) | |
| (11) | ||
| template< class T > std::complex<T> operator/( const std::complex<T>& lhs, const T& rhs); |
(C++20 前) | |
| template< class T > constexpr std::complex<T> operator/( const std::complex<T>& lhs, const T& rhs); |
(C++20 起) | |
| (12) | ||
| template< class T > std::complex<T> operator/( const T& lhs, const std::complex<T>& rhs); |
(C++20 前) | |
| template< class T > constexpr std::complex<T> operator/( const T& lhs, const std::complex<T>& rhs); |
(C++20 起) | |
为复数运算和混合复数/标量运算实现二元运算符。将标量当做拥有等于参数的实部和设为零的虚部的复数。
1-3) 返回其参数的和
4-6) 返回从
lhs 减去 rhs 的结果7-9) 将参数相乘
10-12)
lhs 除以 rhs参数
| lhs, rhs | - | 参数：两个复数，或一个复数与一个拥有匹配类型的标量（ float 、 double 、 long double ） |
返回值
1-3) std::complex<T>(lhs) += rhs
4-6) std::complex<T>(lhs) -= rhs
7-9) std::complex<T>(lhs) *= rhs
10-12) std::complex<T>(lhs) /= rhs
注意
模板实参推导不考虑隐式转换，故这些运算符不能用于整数/复数混合运算。所有情况下，标量必须与复数的底层类型拥有相同类型。
GCC 标志 "-fcx-limited-range" （包含于 "-ffast-math" ）更改复数乘/除的行为，移除浮点极端情况的检查。这会影响向量化。
示例
运行此代码
#include <iostream> #include <complex> int main() { std::complex<double> c2(2, 0); std::complex<double> ci(0, 1); std::cout << ci << " + " << c2 << " = " << ci+c2 << '\n' << ci << " * " << ci << " = " << ci*ci << '\n' << ci << " + " << c2 << " / " << ci << " = " << ci+c2/ci << '\n' << 1 << " / " << ci << " = " << 1./ci << '\n'; // std::cout << 1.f/ci; // 编译错误 // std::cout << 1/ci; // 编译错误 }
输出：
(0,1) + (2,0) = (2,1) (0,1) * (0,1) = (-1,0) (0,1) + (2,0) / (0,1) = (0,-1) 1 / (0,1) = (0,-1)
参阅
| 两个复数，或一个复数与一个标量的复合赋值 (公开成员函数) | |
| 对复数运用一元运算符 (函数模板) |
